2v^2+2v+12=(v-2)

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Solution for 2v^2+2v+12=(v-2) equation: 



2v^2+2v+12=(v-2)

We move all terms to the left:

2v^2+2v+12-((v-2))=0



We calculate terms in parentheses: -((v-2)), so:

(v-2)

We get rid of parentheses

v-2

Back to the equation:

-(v-2)



We get rid of parentheses

2v^2+2v-v+2+12=0

We add all the numbers together, and all the variables

2v^2+v+14=0

a = 2; b = 1; c = +14;
Δ = b2-4ac
Δ = 12-4·2·14
Δ = -111
Delta is less than zero, so there is no solution for the equation

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